Bar Bending Schedule

Enter a member and its reinforcement. Cutting lengths, bar counts and steel weight are worked out as you type — and every bar shows how its figure was reached.

How to Prepare a Bar Bending Schedule (BBS) for RCC Members

  1. 1

    Select Structural Member & Dimensions. Determine the clear span, cross-section dimensions (length, width, depth), and concrete clear cover according to structural drawings and IS 456 Table 16.

  2. 2

    Identify Bar Shapes & Marks. Identify the shape code of each bar group (straight, L-bend, cranked/bent-up, or stirrup/link) and assign unique bar marks (e.g. B1-T1 for top bars, B1-B1 for bottom bars).

  3. 3

    Calculate Cutting Length with Bend Deductions. Add straight leg lengths and hook allowances from IS 2502 Table II, then deduct the bend per Table V: a right-angle bend deducts half the internal radius plus one diameter, and since R = kd that is 2d for mild steel and 3d for IS 1786 deformed bars. Give the result to the next greater whole 25 mm per Clause 5.1.1.

  4. 4

    Determine Number of Bars. For longitudinal bars, use specified bar counts. For stirrups/ties, calculate spacing: (Effective Length / Spacing) + 1.

  5. 5

    Compute Total Length and Steel Weight. Multiply cutting length by the total number of bars across all member instances. Multiply total length by unit weight (D²/162 kg/m) to get total steel weight per diameter.

Turn this into project quantities

Everything above is free. In a QuickBOQ project, Pro writes the finished schedule straight into a steel item's measurement sheet: cutting lengths, bar counts and weight, without typing a single row by hand, and lets you download the 3D rebar cage or bar diagrams as an AutoCAD DXF, 3D mesh, or scale drawing.

Measurement-sheet entry CAD export
See QuickBOQ Pro
Beam

3 bar groups defined

Dimensions and clear cover

Concrete Vol: 0.81 m³
Steel Density: 77 kg/m³Low (120–180 kg/m³)

Total steel

62.76kg

0.63 quintal

Members

1

1 in total

Concrete volume

0.81 m³

77.5 kg/m³

Bar groups

3

Rows

3

Bar markShapeDiaNos × barsCutting lengthTotal lengthkg/mWeight
B1
B1-B10016 mm1 × 36.000 m18.000 m1.57828.40 kg
B1-T10012 mm1 × 26.000 m12.000 m0.88810.66 kg
B1-S1338 mm1 × 401.500 m60.000 m0.39523.70 kg

Steel abstract

DiameterLengthWeight
8 mm60.00 m23.70 kg
12 mm12.00 m10.66 kg
16 mm18.00 m28.40 kg
Net weight62.76 kg
0.00 kg
Total steel62.76 kg
in quintal, as DSR 5.22 is priced0.63

Free to browse. Log in to unlock the full Rate Analysis of every Civil and Electrical item in the latest CPWD DSR.

or see Pro pricing →

Complete Engineering Guide to Bar Bending Schedules (IS 2502 & IS 456)

1. Cutting Length & Bend Deductions (IS 2502 Table V)

A bar bent round a mandrel follows the arc rather than the two straight legs, so the cut length is shorter than the sum of the dimensions taken to the outside of the bend. IS 2502 Table V states it directly: L = A + E − ½R − d, so a right-angle bend deducts ½R + d. Because the internal radius is R = kd, the deduction depends on the steel and the bar size — it is not a single number:

  • Mild steel (k = 2): deduct 2d at 90°
  • Medium tensile (k = 3): deduct 2.5d at 90°
  • IS 1786 deformed (k = 4): deduct 3d at 90°
  • IS 1786 above 25 mm (k = 6): deduct 4d at 90°

2. Hook and Bend Allowances (IS 2502 Table II)

IS 2502 Table II gives the hook allowance H and bend allowance B as functions of k, the internal bend radius in bar diameters (R = kd, Fig. 1 Note 1):k = 2 for mild steel, 3 for medium tensile and 4 for high strength deformed bars to IS 1786 — rising to 3, 4 and 6 respectively above 25 mm. H is then 9d, 11d, 13d or 17d, rounded to the nearest 5 mm and never less than 75 mm. A binder's straight portion beyond the end of the curve is never less than 8d (Cl 3.3), and cutting lengths are given to the next greater whole 25 mm (Cl 5.1.1).

3. Unit Weight Formula (D²/162)

Unit Weight (kg/m) = D² / 162

Where D is the nominal diameter in millimetres. The exact derivation from a steel density of 7,850 kg/m³ gives 162.19, but every printed Indian schedule writes 162 — a difference of 0.12%, and this calculator uses 162 so that its totals reproduce exactly when a checking officer recomputes them by hand. In CPWD DSR (Item 5.22), rebar is billed per quintal (100 kg) or metric tonne (1,000 kg).

4. 1D Stock Cut Optimization (12m Rods)

Steel reinforcement in India is delivered in standard 12-meter commercial stock lengths. QuickBOQ solves the 1D Bin Packing Cutting Stock problem to determine optimal nesting combinations, preventing off-cut scrap from exceeding standard 3% to 5% tender margins.

Frequently asked questions

What is a Bar Bending Schedule (BBS)?

+
A Bar Bending Schedule (BBS) is an organized list of reinforcement bars for an RCC structure. It details the bar mark, diameter, shape description, cutting length, number of bars per member, total bar count, and total weight in kilograms or quintals. It is essential for site fabrication, quantity takeoff, and tender billing.

What bend deduction does IS 2502 specify?

+
IS 2502:1963 Table V gives the bent bar as L = A + E − ½R − d, so a right-angle bend deducts ½R + d. The internal radius is R = kd (Fig. 1 Note 1), so the deduction depends on the steel: 2d for mild steel (k = 2), 2.5d for medium tensile (k = 3), 3d for high strength deformed bars to IS 1786 (k = 4), and 4d for IS 1786 bars above 25 mm (k = 6). Note that Table II gives hook and bend ALLOWANCES — lengths added for an end anchorage — which is a different quantity from the deduction.

What hook allowance does IS 2502 give for stirrups and links?

+
IS 2502:1963 Table II gives the hook allowance H as 9d, 11d, 13d or 17d depending on k, the internal bend radius in bar diameters — k is 2 for mild steel, 3 for medium tensile and 4 for high strength deformed bars to IS 1786, rising to 3, 4 and 6 above 25 mm. H is rounded to the nearest 5 mm and is never less than 75 mm. For a rectangular binder, Table VIII gives the whole bar directly as 2(A + E) + 24d. Clause 3.3 requires the straight portion beyond the end of the curve to be at least 8 times the bar diameter.

How is development length (Ld) calculated per IS 456?

+
Per IS 456:2000 Clause 26.2.1, development length Ld = (ϕ × σs) / (4 × τbd), where ϕ is bar diameter, σs is design stress (0.87 fy), and τbd is design bond stress. For deformed TMT bars (Fe 500) in M25 concrete, standard tension lap is 49d. In compression (Clause 26.2.1.1), τbd increases by 25%, resulting in 39d.

What is the standard unit weight for rebar?

+
IS 1786:2008 Table 1 specifies the nominal mass per metre, which is what the mill certifies and the delivery is weighed against: 6 mm = 0.222, 8 mm = 0.395, 10 mm = 0.617, 12 mm = 0.888, 16 mm = 1.578, 20 mm = 2.466, 25 mm = 3.854, 32 mm = 6.313 kg/m. Site and CPWD hand calculation instead uses D² / 162, which runs 0.12% heavier — 0.889 kg/m for a 12 mm bar against the standard 0.888. QuickBOQ computes on IS 1786 nominal mass by default, offers D² / 162 as an option, and records on every schedule which basis produced it.

How does 1D Stock Cut Optimization work in QuickBOQ BBS?

+
Commercial TMT steel bars in India are supplied in standard 12-meter lengths. QuickBOQ includes a 1D Bin Packing Cutting Stock algorithm that computes optimal cut patterns to minimize off-cut scrap, keeping wastage within standard 3% to 5% tender limits.